Fourier Transform Of Heaviside Step Function

for symmetry, though in many applications, the exact value at the point of discontinuity doesn't affect the integral transform. The Challenge of Direct Integration

Consider the modified function: $$ u(t)e^-\sigma t $$ fourier transform of heaviside step function

We can write the Heaviside function as: $$ u(t) = \frac12 + \frac12\textsgn(t) $$ for symmetry, though in many applications, the exact