New resistance: [ R' = \rho \frac{L'}{A'} = \rho \frac{3L}{A/3} ] [ R' = \rho \frac{3L \times 3}{A} = \rho \frac{9L}{A} ] [ R' = 9 \left( \rho \frac{L}{A} \right) ] [ R' = 9 \times R ]
[ R = \rho \frac{L}{A} ] where:
When the wire is stretched, its volume remains constant. Volume ( V = A \times L = \text{constant} ) ncert solutions
One of the significant benefits of NCERT Solutions is that they provide students with a comprehensive understanding of the subject matter. By using these solutions, students can: New resistance: [ R' = \rho \frac{L'}{A'} =
Original resistance: [ R = \rho \frac{L}{A} = 20 \ \Omega ] ncert solutions